Question

The descending order of the surds $\sqrt[3]{32},\sqrt[6]{63},\sqrt[9]{94}$ is _________.

• A. $\sqrt[9]{94},\sqrt[6]{63},\sqrt[3]{32}$
• B. $\sqrt[9]{94},\sqrt[3]{32},\sqrt[6]{63}$
• C. $\sqrt[3]{32},\sqrt[6]{63},\sqrt[9]{94}$
• D. $\sqrt[6]{63},\sqrt[9]{94},\sqrt[3]{32}$

Answer 1

The correct option is C $\sqrt[3]{32},\sqrt[6]{63},\sqrt[9]{94}$

$\sqrt[3]{32}\approx 1.26$

$\sqrt[6]{63}\approx 1.201$

$\sqrt[9]{94}\approx 1.166$

$\therefore$ Ascending order is $\sqrt[9]{94}<\sqrt[6]{63}<\sqrt[3]{32}$