The correct options are
B a, b, c are in G.P
D (x−α) is a factor of ax2+2bx+c
Given that
∣∣
∣∣abaα+bbcbα+caα+bbα+c0∣∣
∣∣=0
Operating C3→C3−C1α−C2, we get
∣∣
∣
∣∣ab0bc0aα+bbα+c−(aα2+bα+bα+c)∣∣
∣
∣∣=0
or (ac−b2)(aα2+2bα+c)=0
Thus, either a,b,c are in G.P or (x−α) is a factor of ax2+2bx+c.