The determinant Δ=∣∣
∣
∣∣a2+xabacabb2+xbcacbcc2+x∣∣
∣
∣∣ is divisible by
A
x
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B
x2
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C
x3
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D
none of these
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Solution
The correct options are Ax Bx2 Expanding it, =(a2+x)(x)(b2+c2+x)−ab(abx)+ac(−acx) =x(a2b2+a2c2+a2x+xb2+xc2+x2−a2b2−a2c2) =x(a2x+xb2+xc2+x2) =x2(a2+b2+c2+x) So it is divisible by x and x2