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Question

The determinant Δ=∣ ∣ ∣a2+xabacabb2+xbcacbcc2+x∣ ∣ ∣ is divisible by

A
x
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B
x2
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C
x3
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D
none of these
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Solution

The correct options are
A x
B x2
Expanding it,
=(a2+x)(x)(b2+c2+x)ab(abx)+ac(acx)
=x(a2b2+a2c2+a2x+xb2+xc2+x2a2b2a2c2)
=x(a2x+xb2+xc2+x2)
=x2(a2+b2+c2+x)
So it is divisible by x and x2

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