The determinant of an odd order skew symmetric matrix is always :

Zero

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One

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Negative

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Depends on the matrix

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Solution

The correct option is B Zero
$A = - A^{T}$
$d e t A = d e t (- A^{T})$
$d e t A = d e t (- A)$
$d e t A = (- 1)^{n}$ det A, where n is the order of the matrix.
if n is odd , let n=1
then $d e t A = - 1 d e t A$
$2 d e t A = 0$
$d e t A = 0$

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Similar questions

Determinant of skew symmetric matrix is always 0.

A = ⎡ ⎢ ⎣ \begin{matrix} 0 & 1 & 2 - 1 & 0 & 3 - 2 & - 3 & 0 \end{matrix} ⎤ ⎥ ⎦

A = [a_{i j}]_{5 \times 5}

a_{i j} + a_{i j} = 0

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