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Question

The determinant △=∣∣ ∣ ∣∣a2(1+x)abacabb2(1+x)bcacbcc2(1+x)∣∣ ∣ ∣∣ is divisible by

A
1+x
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B
(1+x)2
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C
x2
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D
x2+1
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Solution

The correct option is A 1+x
=∣ ∣ ∣a2(1+x)abacabb2(1+x)bcacbcc2(1+x)∣ ∣ ∣
Put a=b=c=1
=∣ ∣ ∣(1+x)111(1+x)111(1+x)∣ ∣ ∣
We can see that it is divisible by (1+x)

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