The correct option is B False
Let Δ=∣∣
∣∣1abc1bca1cab∣∣
∣∣=1abc∣∣
∣
∣∣aa2abcbb2abccc2abc∣∣
∣
∣∣
Applying R1→aR1,R2→bR2,R3→cR3
=1abc.abc∣∣
∣
∣∣aa21bb21cc21∣∣
∣
∣∣=∣∣
∣
∣∣1aa21bb21cc2∣∣
∣
∣∣
∣∣
∣∣1abc1bca1cab∣∣
∣∣=∣∣
∣
∣∣1aa21bb21cc2∣∣
∣
∣∣
Hence, statement is false.