The diagonal of a parallelogram divides it into two congruent triangles.

True

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False

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Solution

The correct option is A
True

$Δ A B D$ and $Δ C D B$

AB = CD (Opposite sides of a parallelogram)

AD = CB (Opposite sides of a parallelogram)

BD = DB (Common)

So, $Δ A B D$ $≅$ $Δ C D B$ (By SSS congruence condition)

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Similar questions

Prove that a diagonal of a parallelogram divides it into two congruent triangles.

Given: Area of parallelogram = Base $\times$ Height

Statement 1: A diagonal of a parallelogram divides it into two congruent triangles.

Statement 2: Areas of two congruent triangles are exactly equal.

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