The diagonal of a quadrilateral shaped field is $24$ m and the perpendiculars dropped on it from the remaining opposite vertices are $8$ m and $13$ m. Find the area of the field.

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Solution

Area of quadrilateral = $\frac{1}{2}$ $\times$ $D i a g o n a l$ $\times$ [Sum of the perpendiculars on the diagonal from opposite vertices ]

= $\frac{1}{2} \times 24 \times (8 + 13) m^{2}$ = $252$ m $^{2}$

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The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

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The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Q. If the diagonal of a quadrilateral shaped field is

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and the perpendiculars dropped on it from the remaining opposite vertices are

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, then the area of the field is

The diagonal of a quadrilateral shaped field is 25m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 12m. Find the area of the field(in m²).

The diagonal of a quadrilateral shaped field is 25 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 12 m. Therefore the area of the field is 250m².

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The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Area of quadrilateral = 12 × Diagonal × [Sum of the perpendiculars on the diagonal from opposite vertices ] = 12×24×(8+13)m2 = 252 m2

The diagonal of a quadrilateral shaped field is $24$ m and the perpendiculars dropped on it from the remaining opposite vertices are $8$ m and $13$ m. Find the area of the field.

Area of quadrilateral = $\frac{1}{2}$ $\times$ $D i a g o n a l$ $\times$ [Sum of the perpendiculars on the diagonal from opposite vertices ]

= $\frac{1}{2} \times 24 \times (8 + 13) m^{2}$ = $252$ m $^{2}$