Question

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Answer 1

In quadrilateral shaped field ABCD, diagonal AC = 24 m

and perpendicular BL = 13 m and perpendicular DM on AC = 8 m

$\therefore AreaofthefieldABED=\frac{1}{2}AC\times (BL+DM)=\frac{1}{2}\times 24\times (13+8)m^2=12\times 21=252m^2$