The diagonal of a quadrilateral shaped field is 25 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 12 m. Therefore the area of the field is 250m².

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

250

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

300

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Area of quadrilateral = $\frac{1}{2}$ (d₁) × (h₁ + h₂)

= $\frac{1}{2}$ (25)(8 + 12)

= 250m²

Suggest Corrections

Similar questions

The diagonal of a quadrilateral shaped field is 25m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 12m. Find the area of the field(in m²).

Q. The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 12m. Find the area of the field(in m²).

The diagonal of a trapezium shaped field is 25m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 12m. Find the area of the field(in m²).

Q. If the diagonal of a quadrilateral shaped field is

24 m

and the perpendiculars dropped on it from the remaining opposite vertices are

8 m

and

13 m

, then the area of the field is

The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 12m. Find the area of the field in $m^{2}$ .

Join BYJU'S Learning Program

The diagonal of a quadrilateral shaped field is 25 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 12 m. Therefore the area of the field is 250m2.

Area of quadrilateral = 12 (d1) × (h1 + h2) = 12 (25)(8 + 12) = 250m2

The diagonal of a quadrilateral shaped field is 25 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 12 m. Therefore the area of the field is 250m².

Area of quadrilateral = $\frac{1}{2}$ (d₁) × (h₁ + h₂)

= $\frac{1}{2}$ (25)(8 + 12)

= 250m²