Question

The diagonal of a rectangular is $60$ m more than its shorter side and the larger side is $30$ m more than the shorter side. Find the side of the rectangle.

Answer 1

Let the shorter side,$s$ be $x$

larger side,$l=x+30$

diagonal,$d=x+60$

Atp

$d^2=l^2+s^2$

$(x+60{)}^2=(x+30{)}^2+x^2$

$120x+3600=60x+900+x^2$

$x^2-60x-2700=0$

$x=90$ or $-30$

Hence, $x=90$

$s=90,l=120$