Question

The diagonal of a square A is $(x+y)$. The diagonal of square B with twice the area of A is

• A. $\sqrt{2}(x+y)$
• B. $2(x+y)$
• C. $2x+4y$
• D. $4x+2y$

Answer 1

Answer: (A), (D)

$\sqrt{2}(x+y)$
$4x+2y$

The diagonal of a square $=x+y$. If $a$ be the side of a square then $2a^2=(x+y{)}^2$. Also the area of the square $B=2a^2$ because area of $B=2\times areaofA$.
$\therefore 2a^2=(x+y{)}^2$
$\therefore$ Each side of the square $B=(x+y)$
$\therefore$ Diagonal of the square $=\sqrt{2}(x+y)$