The diagonals AC and BD of rectangle ABCD intersect at point K. If l(AK) = 3.5 cm, find l(KC) and l(AC).

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Solution

In rectangle ABCD,
AB and CD intersect at point K; l(AK)=3.5 cm.
So, l(AK) = l (KC) (Diagonals of a rectangle bisect each other)
and l (BK) = l (DK) (Diagonals of a rectangle bisect each other)
l (AK) = l (KC) = 3.5 cm
and l (AC) = l (AK) + l (KC) = 3.5 cm + 3.5 cm = 7 cm
∴ l (KC) = 3.5 cm
l (AC) = 7 cm

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