The correct option is C 160
Given that, diagonals are 16 cm and 20 cm.
It is also given that two diagonals intersect each other at right angles.
We know that diagonals intersect each other at right angles in square, kite and rhombus.
It can't be square because the length of diagonals are different.
Thus, the given parallelogram would be a kite or a rhombus.
The area of kite or rhombus, A= 12(d1×d2)
where, d1and d2 are length of diagonals of the parallelogram.
A = 12(16 × 20) = 160
Hence, area of parallelogram is 160 sq. cm.