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Question
The diagonals of a parallelogram PQRS are along the lines x + 3y = 4 and 6x – 2y = 7. Then PQRS must be
The diagonals of a parallelogram PQRS are along the lines x + 3y = 4 and 6x – 2y = 7. Then PQRS must be
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Solution
The correct option is D Rhombus
As product of slope of these two lines is –1, hence these diagonals are perpendicular. So, PQRS must be a rhombus.
Rhombus
As product of slope of these two lines is –1, hence these diagonals are perpendicular. So, PQRS must be a rhombus.
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