Question

The diagonals of a rectangle ABCD meet at O. If $\angle$BOC = ${44}^{\circ }$, find $\angle$OAD.

• A. 68°
• B. 88°
• C. 72°
• D. 56°

Answer 1

The correct option is A

68°

$\angle$AOD = ${44}^{\circ }$ (vertically opposite)

$\angle$ODA = $\angle$OAD (Isosceles triangle)

$\angle$OAD = $\frac{{180}^{\circ }-{44}^{\circ }}{2}={68}^{\circ }$