The diagonals of a rhombus are 24 cm and 10 cm. What is the perimeter of the rhombus ?

52

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50

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54

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48

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Solution

The correct option is A $52$ cm
Each side $= \sqrt{{(\frac{24}{2})}^{2} + {(\frac{10}{2})}^{2}} = \sqrt{144 + 25} = \sqrt{169} = 13 c m$
$∴ P e r i m e t e r = 4 \times 13 c m = 52 c m$

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