Question

The diagonals $PR$ and $QS$ of a Rhombus $PQRS$ are $20cm$ and $48cm$ respectively. Find the length of side $PQ$.

Answer 1

By the formula of square root

$a^2=(\frac{d^2}{4}+\frac{d^2}{4})=(\frac{{20}^2}{2}+\frac{{48}^2}{2})$

$a^2=$$(100+576)$

$a^2=676$

$a=26cm$

length of side $PQ=26cm$