CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The diagram below represents five different same-length identical wires(red) carrying the same amount of current in the same magnetic field (blue) with current directions and magnetic field directions indicated by arrows.
Which wire(s) experience(s) the most force due to the magnetic field?
494382_3a4cecd2372947089689505d5f31508c.png

A
3 only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 and 5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1 only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
1 and 4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is E 1 and 4
The equation for the force on a current-carrying wire in a magnetic field is F=BILsinθ, where theta is the angle between the current direction and the direction of the magnetic field.
The more a wire cuts across the field lines, the greater the force. In the equation, the closer theta is to ninety degrees, the greater the force. The closer theta is to zero or one hundred eighty degrees, the closer the force is to zero.
In this case, wires 1 and 4 are at ninety degrees to the magnetic field.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Evidences of Evolution
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon