The diagram (fig.) shows a venturimeter, through which water is flowing. The speed of water at a is 2 cm/sec. The speed of water at Y (taking $g = 1000 c m / s e c^{2}$ ) is :-

23 c m / s e c

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32 c m / s e c

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101 c m / s e c

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1024 c m / s e c

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Solution

The correct option is B $32 c m / s e c$
The height difference between the points x and y is 5.1 mm

Therefore, the pressure difference between the 2 points will be,

$P = ρ g h$

$P = 1 \times 1000 \times 0.51$

P = 510

Applying Bernoulli's theorem,

$δ P + 0.5 ρ δ v^{2} = 0$

$δ P = 510$

$510 = 0.5 \times 1 \times (v_{2}^{2} - 2^{2})$

Hence, $v_{2}^{2} = 1024 o r v_{2} = 32 c m / s e c$

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The diagram (fig.) shows a venturimeter, through which water is flowing. The speed of water at a is 2 cm/sec. The speed of water at Y (taking g=1000cm/sec2) is :-

The correct option is B 32cm/secThe height difference between the points x and y is 5.1 mmTherefore, the pressure difference between the 2 points will be,P=ρghP=1×1000×0.51P = 510Applying Bernoulli's theorem,δP+0.5ρδv2=0δP=510510=0.5×1×(v22−22)Hence, v22=1024 or v2=32cm/sec

The diagram (fig.) shows a venturimeter, through which water is flowing. The speed of water at a is 2 cm/sec. The speed of water at Y (taking $g = 1000 c m / s e c^{2}$ ) is :-