Question

The diagram represents the preparation of sodium sulphate salt from dilute $H_{2}S{O}_4$ acid and sodium hydroxide. State why titration is conducted for the preparation of copper [II] sulphate crystals by neutralization?

• A. In acid solutions there are more $H^{+}$ ions than $O{H}^{-}$ ions
• B. In alkaline solution there are more $O{H}^{-}$ ions than $H^{+}$ ions
• C. Forms an insoluble solid product
• D. To know end point of titration and and to check if neutralisation is completed

Answer 1

Answer: (D)

To know end point of titration and and to check if neutralisation is completed

During the preparation of sodium sulphate

we have, $H_{2}S{O}_4+2NaOH\to N{a}_{2}S{O}_4+H_{2}O$

during this acid base reaction, titration is done to know the endpoint and to check the complete neutralisation.