The diagram shows a scalene triangle, ABC, with vectors −−→AB=3^a and −−→BC=2^b. The point M is the midpoint of AC.Find an expression for the vector −−→AM in terms of ^a and ^b.
First we can find the vector −−→AC
−−→AC=−−→AB+−−→BC=3^a+2^b
Since, M is the midpoint of AC we know that −−→AM=12−−→AC
Thus, −−→AM=12(3^a+2^b)=(32^a+^b)