wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The diagram shows a sphere of radius R that has a charge density described by the function =Ar.
Which of the following expressions gives the electric field strength at point P, a point that lies outside the sphere and is at a distance r from the center of the sphere?
495966_4ed10570b1724c64bd7a21eb2246b765.png

A
AR28πϵ0r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
AR43ϵ0r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
AR48ϵ0r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
AR33ϵ0r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
AR44ϵ0r2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is E AR44ϵ0r2
The total charge on the sphere is Q=R0ρdV=R0(Ar)4πr2dr=πAR4
By Gauss's law, the electric field at distance r>R from centre is
E.4πr2=Qinϵ0=Qϵ0
or E=πAR44πϵ0r2=AR44ϵ0r2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising Electric Fields - Electric Field Lines
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon