The diagram shows the change of phase of a substance on a temperature-time graph. What is the melting point of the substance?

t_{1}^{\circ} C

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t_{2}^{\circ} C

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t_{3}^{\circ} C

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t_{4}^{\circ} C

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Solution

The correct option is A $t_{1}^{\circ} C$
From the curve, melting point is $t_{1}^{o} C$
In part $A B$ , state is solid and temperature is rising.
In part $B C$ , there is change of state from solid to liquid, i.e., this stage is melting, without change in temperature.
In part $C D$ , state is liquid and temperature is rising.
In part $D E$ , there is change of state from liquid to gas, i.e., this stage is vaporization, without change in temperature.
In part $E F$ , state is gas and temperature is rising.

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Similar questions

The diagram below shows the change of phases of a substance on a temperature-time graph on heating the substances at a constant rate.

(a) What do the parts AB, BC, CD and DE represent?

(b) What is the melting point of the substance?

t_{1}, t_{2}, t_{3}, t_{4}

x y = c^{2}

t_{1}, t_{2}, t_{3}

A (c t_{1}, \frac{c}{t_{1}})

B (c t_{2}, \frac{c}{t_{2}})

C (c t_{3}, \frac{c}{t_{3}})

D (c t_{4}, \frac{c}{t_{4}})

x^{2} + y^{2} + 2 g x + 2 f y + k = 0

t_{1} + t_{2} + t_{3} + t_{4} = - \frac{2 g}{c}

A, B, C, D

x y = c^{2}

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