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Distance vs Time Graph

The diagram s...

Question

The diagram shows the displacement time graph for a particle moving in a straight line. The average velocity for the internal $t = 0, t = 5$

0

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6m/s6m/s

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- 2 m / s

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2 m / s

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Solution

The correct option is D $2 m / s$
$\begin{matrix} A v e r a g e v e l o c i t y = \frac{d i s p l a c e m e n t}{t o t a l t i m e} w e n e e d t o f i n d o u t t h e a v e r a g e v e l o c i t y f o r w h o l e t i m e i n t e r v a l t h a t i s 10 s . p a r t i c l e s t a r t s f r o m 60 m i n 0 sec o n d s a n d r e a c h t o 40 m i n 10 sec o n d s a f t e r c o v e r i n g d i s tan c e 50 m a n d 30 m i n 6 m i n sec o n d s a n d 4 sec o n d s r e p e c t i v e l y . s o n e t d i s p l a c e m e n t i s 60 - 40 = 20 m t i m e = 10 s a v e r a g e v e l o c i t y = \frac{20}{10} = 2 m / s \end{matrix}$
Hence,
option $(D)$ is correct answer.

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