The diagram shows the use of a lever. If FA = 10 cm, AB = 500 cm, calculate the minimum effort required to lift the load.

1550 N

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2000 N

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2550 N

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5100 N

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Solution

The correct option is C
2550 N

Given : Effort arm FA = 10 cm

Load arm, BF = 500 + 10 = 510 cm

Mechanical Advantage = $\frac{E f f o r t a r m}{L o a d a r m} = \frac{10}{510} = \frac{1}{51}$

Also, Effort $\times$ Effort arm FA = Load $\times$ Load arm BF

$\Rightarrow$ E $\times$ 10 = 50 $\times$ 510

$\Rightarrow$ E = $\frac{50 \times 510}{10}$ = 2550 N

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