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Question

The diagram shows the velocity against time graph for the motion of a body along a straight path. What is its displacement in the first 5 s?

A
3 m
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B
5 m
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C
7 m
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D
9 m
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Solution

The correct option is D 9 m
We know that area under the velocity-time curve gives the displacement.

So,

Displacement = Area of trapezium OABC +Area of triangle BCD +Area of triangle DFE

d=12×(2+4)×3+12×1×4+12×1×(4)

d=9 m

Hence, option (D) is the correct answer.

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