The diagram shows three circles externally tangent to each other and to a semicircle.The shaded area is 120 sq.units. The area of the unshaded parts of the semi circle in square units is
80
40
Be x units and y units respectively. Draw PK perpendicular to QO.
The radius of the circle with centre Q is r units.Now,
PQ=(r+x) units,
QK= (r-x) units and
OP=OL-PL=(2r-x) units.
From right angled ∆PQK, PQ2-QK2=PK2= OP2-OK2
i.e., (r+x)2 - (r-x)2 = PK2 = (2r-x)2-x2
or4rx = 4r2 - 4rx
or8rx= 4r2
Hence r=2x