Question

The diagrams a, b, c, d and e show arrangement of stamens based on their cohension. Choose the correct answer.

• A. a-Hibiscus rosa-sinensis, b-Helianthus annuus, c-Cucurbita pepo, d-Crotalaria juncea, e-Bombyx ceiba
• B. a- Hibiscus rosa-sinensis, b-Bombyx ceiba c-Helianthus annuus, d-Cucurbita pepo, e-Helianthus annuus
• C. a-Hibiscus rosa-sinensis, b-Bombyx ceiba, c-Helianthus annuus, d-Cucurnita pepo, c-Helianthus annuus, d-Cucurbita pepo, e-Crotalaria juncea
• D. a-Hibiscus rosa-sinensis, b-Crotalaria juncea, c-Bombyx ceiba, d-Helianthus annuus, e-Cucurbita pepo

Answer 1

The correct option is D

a-Hibiscus rosa-sinensis, b-Crotalaria juncea, c-Bombyx ceiba, d-Helianthus annuus, e-Cucurbita pepo

(a) The monadelphous condition of androecium has filaments united to form a single bundle. It is seen in Hibiscus rosa-sinensis (Malvaceae).

(b) The diadelphous condition of androecium has filaments united to form two bundles in the 9+1 pattern. It is seen in Crotolaria juncea (Fabaceae).

(c) The polyadelphous condition of androecium has filaments united to form multiple bundles. It is seen in Bombyx ceiba (Malvaceae).

(d) In the syngenesious condition of the androecium, the anthers are united while filaments are free, it is seen in Helianthus annuus, (Asteraceae).

(e) In the synandrous condition of androecium, the stamens are fused throughout their length. It is seen in Cucurbita pepo.

Hence, the correct answer is 'Option D'.