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Question

The diameter D of a wire is measured using screw gauge of zero error. Then:

A
D= main scale reading + circular scale divison × LC
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B
D= circular scale reading + circular scale reading × LC
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C
D= main scale reading + vernier scale reading × LC
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D
None of the above
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Solution

The correct option is C D= main scale reading + circular scale divison × LC
The diameter D of the wire is given as :

D= main scale reading +circular scale divison × L.C
where L.C. is least count of the screw gauge.

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