The diameter of a cylinder jar is increased by 25%. By what percent must the height of the jar be decreased so that there is no change in its volume?
36 %
Volume of a cylinder = (π×r2×h)
Diameter is increased by 25 % hence radius of the cylinder is also increased by 25 %.
As per the question, volume remains the same that means height should be decreased.
Let the new height be h’.
After the increment of radius of cylinder volume = (π×(1.25r)2×h′).
Equating both the equation, we have,
(π×r2×h) = (π×(1.25r)2×h′)
⇒h=2516h′
⇒h′h=1625
⇒[h–h′h] ×100% = (25−1625) ×100% =36%
⇒Height decrement=36%