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Standard XII

Physics

SHM expression

The diameter ...

Question

The diameter of a flywheel is $1 m$ . It has a mass of $20 k g$ . It is rotating about its axis with a speed of $120$ rotations in one minute. Its angular momentum in $k g m^{2} / s$ is :

13.4

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31.4

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41.4

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Solution

The correct option is D 31.4
$w = 120 r p m$

Considering it a disc
$L = I w$

$= \frac{20}{2} \times (\frac{1^{2}}{4}) \times 120 \times \frac{2 π}{60}$

$= 31.415 k g m^{2} / s$

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The diameter of a flywheel is 1m. It has a mass of 20kg. It is rotating about its axis with a speed of 120 rotations in one minute. Its angular momentum in kgm2/s is :

The correct option is D 31.4w=120rpm Considering it a discL=Iw=202×(124)×120×2π60=31.415kgm2/s

The diameter of a flywheel is $1 m$ . It has a mass of $20 k g$ . It is rotating about its axis with a speed of $120$ rotations in one minute. Its angular momentum in $k g m^{2} / s$ is :

The correct option is D 31.4
$w = 120 r p m$

Considering it a disc
$L = I w$

$= \frac{20}{2} \times (\frac{1^{2}}{4}) \times 120 \times \frac{2 π}{60}$

$= 31.415 k g m^{2} / s$