wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

The diameter of a garden roller is 1.4 m and it is 2 m long. Total area covered in 5 revolutions is

A
4.4 m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8.8 m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
44 m2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
84 m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 44 m2
A roller is cylindrical shaped.
Height (h) of the cylindrical roller = length of roller = 2 m
Diameter of the roller = 1.4 m
Radius (r) of the roller = 0.7 m

We need to calculate the area covered in 5 revolutions of this roller.

Area covered=CSA of the roller×Number of revolutions

We know, CSA of a cylinder with radius 'r' and height 'h' is 2πrh.
Then, CSA of the roller=2×227×0.7×2=8.8 m2

Hence,
Area covered =(8.8×5) m2=44 m2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Surface Area of Solids
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon