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The diameter ...

Question

The diameter of a hole is given as $50_{+ 0.00}^{+ 0.15} m m$ . The upper limit on the dimensions in mm, of the shaft for achieving maximum interference of 50 microns is
50.05

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Solution

The correct option is A 50.05
$Maximum Interference = Maximum shaft diameter-Minimum hole diameter$

$0.05 = {Shaft}_{max} - 50$

${Shaft}_{max} = 50.05 m m$

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