The diameter of a hollow pipe is 6 cm and it is 14 cm long. What would be the cost of cementing its outer surface if the cost of cementing is ₹ 100 per cm2?
Given,
Diameter = 6 cm
⇒ Radius of the pipe, r =62=3 cm
Height, h = 14 cm
Area to be cemented = Curved surface area of the cylinder (hollow pipe) =2πrh
=2×227×3×14
=2×22×3×2
=44×6
=264 cm2
Cost of cementing = ₹ 100 per cm2
Total cost = 264 x 100 = ₹ 26,400
Therefore, cost of cementing outer surface = ₹ 26,400