The diameter of a lead ball is 2.1 cm. The density of the lead used is 11.34 g/cm $^{3}$ . What is the weight of the ball?

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Solution

Given diameter $= 2.1 c m$

Then radius $= 1.05 c m$

Volume of sphere $= \frac{4}{3} π r^{3} = \frac{4}{3} \times \frac{22}{7} \times (1.05)^{3} c m^{3} = 4.86 c m^{3}$

Given density $= \frac{m a s s}{v o l u m e} = 11.34 g m / c m^{3}$

Then mass of ball $= 11.34 \times 4.86 = 55.11 g m$

$m a s s \times a c c e l e r a t i o n d u e t o g r a v i t y = w e i g h t$

Converting to SI units:

mass of ball $= 0.05511 k g$

acceleration due to gravity $= 9.81 m / s^{2}$

$w e i g h t o f b a l l = 0.05511 \times 9.81 = 0.540 k g$

Hence, the weight of the ball is $0.540 k g$ .

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The diameter of a lead ball is 2.1 cm. The density of the lead used is 11.34 g/cm3. What is the weight of the ball?

The diameter of a lead ball is 2.1 cm. The density of the lead used is 11.34 g/cm $^{3}$ . What is the weight of the ball?