The diameter of a metallic sphere is equal to $9 c m$ . It is melted and drawn into a long wire of diameter $2 m m$ having a uniform cross-section. Find the length of the wire.

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Solution

$\frac{4}{3} π r^{3} = π r^{' 2} h^{'}$

$\Rightarrow h^{'} = \frac{4 (4.5)^{3}}{3 (0.1)^{2}} = 12150 c m = 121.5 m$

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The diameter of a metallic sphere is equal to 9cm. It is melted and drawn into a long wire of diameter 2mm having a uniform cross-section. Find the length of the wire.

43πr3=πr′2h′⇒h′=4(4.5)33(0.1)2=12150cm=121.5m

The diameter of a metallic sphere is equal to $9 c m$ . It is melted and drawn into a long wire of diameter $2 m m$ having a uniform cross-section. Find the length of the wire.

$\frac{4}{3} π r^{3} = π r^{' 2} h^{'}$

$\Rightarrow h^{'} = \frac{4 (4.5)^{3}}{3 (0.1)^{2}} = 12150 c m = 121.5 m$