Question

The diameter of a piston $P_2$ is $50cm$ and that of a piston $P_1$ is $10cm$. What is the force exerted on $P_2$ when a force of $1N$ is applied on $P_1$?

Answer 1

$\frac{A_1}{A_2}=\frac{D_1^2}{D_2^2}=\frac{1}{25}$

Since, Pressure = constant

$P_1=P_2$

$\frac{F_1}{F_2}=\frac{A_1}{A_2}=\frac{1}{25}$

$1=\frac{F_2}{25}\Rightarrow F_2=25N$