The diameter of a rod was found to be 23.7 mm using a standard vernier caliper. The M.S.R and V.C.D. on another vernier calipers in which 1 M.S.D. =0.5mm and the least count is 0.05 mm are divisional and respectively.

23,7

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23,14

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47,4

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46,14

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Solution

The correct option is B 47,4
$\begin{matrix} Diameter of rod = 23.7 m m 1 M . S . D = 0.5 m m Least count = 0.05 m m 1 V . S . D . = 1 M . S . D . - Least count \end{matrix}$

$\begin{matrix} Now, 23.7 \div 0.5 \Rightarrow Quetient = 47, Remainder = 0.2 Now, 0.2 \div (0.05) \Rightarrow Quotient = 4 \end{matrix}$
Hence option C is correct

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The diameter of a rod was found to be 23.7 mm using a standard vernier caliper. The M.S.R and V.C.D. on another vernier calipers in which 1 M.S.D. =0.5mm and the least count is 0.05 mm are ______ divisional and ______ respectively.

The correct option is B 47,4 Diameter of rod =23.7 mm1M.S.D=0.5 mm Least count =0.05 mm1 V.S.D.=1M.S.D. - Least count Now, 23.7÷0.5⇒ Quetient =47 , Remainder =0.2 Now, 0.2÷(0.05)⇒ Quotient =4Hence option C is correct

The diameter of a rod was found to be 23.7 mm using a standard vernier caliper. The M.S.R and V.C.D. on another vernier calipers in which 1 M.S.D. =0.5mm and the least count is 0.05 mm are divisional and respectively.