The diameter of a roller 84 cm long is 1.5 m. If it takes 100 revolutions to level a playground, find the cost of levelling this ground at the rate of ₹ 0.50 per square metre.
₹ 198
We have d = 1.5 m, r=1.52=1520 m=34 m
and h=84 cm=84100 m
∴ Area covered in 1 revolution =2πrh=2×227×34×84100=44×9100m2
∴ Area covered in 100 revolutions =100×44×9100=396 m2
∴ Cost of levelling the playground =₹0.50×396=₹ 198