The diameter of a roller is 84cm and its length is 120cm. It take 500 complete revolutions to move once over to level a playground. Find the area of the playground in m×m.

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Solution

Solution
It can be observed that a roller is cylindrical.
Height (h) of cylindrical roller = Length of roller = 120 cm
Radius (r) of the circular end of roller =(84/2)cm=42 cm
CSA of roller =2πrh
=31680 cm^2
Area of field =500×CSA of roller
=(500×31680)cm^2=15840000 cm2=1584m^2

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The diameter of a roller is 84cm and its length is 120cm. It take 500 complete revolutions to move once over to level a playground. Find the area of the playground in m×m.

Solution It can be observed that a roller is cylindrical. Height (h) of cylindrical roller = Length of roller = 120 cm Radius (r) of the circular end of roller =(84/2)cm=42 cm CSA of roller =2πrh =31680 cm^2 Area of field =500×CSA of roller =(500×31680)cm^2=15840000 cm2=1584m^2

Solution
It can be observed that a roller is cylindrical.
Height (h) of cylindrical roller = Length of roller = 120 cm
Radius (r) of the circular end of roller =(84/2)cm=42 cm
CSA of roller =2πrh
=31680 cm^2
Area of field =500×CSA of roller
=(500×31680)cm^2=15840000 cm2=1584m^2