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The diameter of a solid metallic sphere is equal to the inner diameter of a hollow metallic sphere. If inner diameter of hollow sphere is two thirds of its outer diameter. Both the spheres are made of same metal. If an equal amount of heat is supplied the both the spheres. Find the ratio of increase in temperature of the solid sphere to that of the hollow one?

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Solution

Given: The diameter of a solid metallic sphere is equal to the inner diameter of a hollow metallic sphere. If inner diameter of hollow sphere is two thirds of its outer diameter. Both the spheres are made of same metal. If an equal amount of heat is supplied the both the spheres.
To find the ratio of increase in temperature of the solid sphere to that of the hollow one
Solution:
We know that,
Heat transfer = Q=mcΔT
Where, m=mass, c=specific heat capacity, ΔT=temperature.
Q=ρVcΔT (where ρ=density, V=volume, as m=ρV)
Now if there are two bodies to which equal amount of heat supplied and are of same metal.
Q1=ρ1V1c1ΔT1
Q2=ρ2V2c2ΔT2
If same metal (ρ1=ρ2,c1=c2)
Ratio of increase in temperature
ΔT1ΔT2=V2V1.....(i)
Now in question,
Let the diameter of solid sphere be = d
Inner diameter of hollow sphere = d
Outer diameter of hollow sphere =32d
temperature rise in solid sphere = ΔT1
temperature rise in hollow sphere=ΔT2
According to equation (i)
ΔT1ΔT2=V2V1
Volume of hollow sphere =43π(r32r31)
r2=outer radius
r1= inner radius
Volume of solid sphere =43πr3
ΔT1ΔT2=4π3[(27d364d38)]4π3[d38]=2786418ΔT1ΔT2=1964×8ΔT1ΔT2=198
is the the ratio of increase in temperature of the solid sphere to that of the hollow one

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