Question

The diameter of a wire as measured by a screw gauge was found to be $1.002cm$, $1.004cm$ and $1.006cm$. The absolute error in the third reading is:

• A. $0.002cm$
• B. $0.004cm$
• C. zero
• D. $1.002cm$

Answer 1

Answer: (A)

$0.002cm$

For the three readings:

$mean=\frac{1.002+1.004+1.006}{3}cm=1.004cm$

So, absolute error in the third reading:

$\Delta D_3=1.006-mean$
$=(1.006-1.004)cm$
$=0.002cm$