Question

The diameter of the base of a cylindrical drum is $35dm$ and its height is $24dm$. It is full of kerosene. How many tins, each of size $25cm\times 22cm\times 35cm$, can be filled with kerosene from the drum? $(\pi =\frac{22}{7})$

• A. $1200$
• B. $1020$
• C. $600$
• D. $120$

Answer 1

The correct option is A $1200$

Volume of a Cylinder $=\pi R^{2}h$

Radius of the drum $=\frac{Diameter}{2}=\frac{35}{2}dm=\frac{350}{2}cm$

Height $=24dm=240cm$

The tin is in the shape of a cuboid.

Volume of a cuboid $=l\times b\times h$

Required number of tins $=\frac{\text{Volume of drum}}{\text{Volume of 1 tin}}=\frac{\frac{22}{7}\times \frac{350}{2}\times \frac{350}{2}\times 240}{25\times 22\times 35}=1200$