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Question

The diameter of the eye-ball of a normal eye is about 2.5 cm. The power of the eye lens varies from

A
2 D to 10 D
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B
40 D to 32 D
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C
9 D to 8 D
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D
44 D to 40 D
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Solution

The correct option is D 44 D to 40 D
An eye sees distant objects with full relaxation so 12.5×1021=1f or
P=1f=125×102=40D
An eye sees an object at 25 cm with strain so 12.5×102125×102=1forP=1f=40+4=44D

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