Question

The diameter of two circles are $32cm$ and $24cm$. Find the radius of the circle having its area equal to sum of the area of the two given circle.

• A. $20cm$
• B. $18cm$
• C. $52cm$
• D. $60cm$

Answer 1

The correct option is A $20cm$

Sum of area given circle=${\left(\frac{32}{2}\right)}^2+{\left(\frac{24}{2}\right)}^2$

=$\pi (16{)}^2+\pi (12{)}^2$
Let, radius of the circle be r
$\therefore \pi r^2=\pi (16{)}^2+(12{)}^2$
$=>r^2=256+144$
$=>r=\sqrt{400}$
$=>r=20cm$