The diameter of zinc atom is.Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

Open in App

Solution

(a) Radius of zinc atom

(b) Length of the arrangement = 1.6 cm

= 1.6 × 10^–2 m

Diameter of zinc atom = 2.6 × 10^–10 m

∴ Number of zinc atoms present in the arrangement

Suggest Corrections

Similar questions

The diameter of zinc atom is 2.6 A. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

2× $10^{8}$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Q. What is the number of zinc atoms in a piece of zinc weighing 10 g ? (Atomic mass of Zn = 65 u)

2 \times 10^{8}

atom of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Q. Cs atoms are the largest naturally occurring atoms. The radius of Cs atom is

2.6 ˚ A

. The number of moles of Cs atoms to be laid side by side to give a row of Cs atoms 2.50 cm long is

x \times 10^{- 17}

. The value of x is

Join BYJU'S Learning Program

The diameter of zinc atom is.Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

(a) Radius of zinc atom (b) Length of the arrangement = 1.6 cm = 1.6 × 10–2 m Diameter of zinc atom = 2.6 × 10–10 m ∴ Number of zinc atoms present in the arrangement

(a) Radius of zinc atom

(b) Length of the arrangement = 1.6 cm

= 1.6 × 10^–2 m

Diameter of zinc atom = 2.6 × 10^–10 m

∴ Number of zinc atoms present in the arrangement