The diameters of a circle are along 2x+y-7 and x+3y-11=0 Then the equation of this circle,which also passes through (5,7) is

x²+y²-4x-6y-16=0

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x²+y²-4x-6y-20=0

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x²+y²-4x-6y-12=0

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x²+y²+4x+6y-12=0

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Solution

The correct option is C
x²+y²-4x-6y-12=0

C = (2, 3) r = 5 Equation of circle is $(x - 2)^{2} + (y - 3)^{2} = 5^{2}$

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The diameters of a circle are along 2x+y-7 and x+3y-11=0 Then the equation of this circle,which also passes through (5,7) is

The correct option is C x2+y2-4x-6y-12=0 C = (2, 3) r = 5 Equation of circle is (x−2)2+(y–3)2=52

The correct option is C
x²+y²-4x-6y-12=0

C = (2, 3) r = 5 Equation of circle is $(x - 2)^{2} + (y - 3)^{2} = 5^{2}$