Question

The diameters of the front and rear wheels of a tractor are 80 cm and 2 m respectively. Find the number of revolutions that a rear wheel makes to cover the distance which the front wheel covers in 800 revolutions.

Answer 1

Radius of front wheel $=40cm=\frac{2}{5}$ m

Circumference of the front wheel $=(2\pi \times \frac{2}{5})m=\frac{4\pi }{5}$

Distance covered by the front wheel in 800 revolutions $=(\frac{4\pi }{5}\times 800)m=\left(640\pi \right)$ m

Radius of the rear wheel = 1 m

Circumference of the rear wheel $=(2\pi \times 1)=2\pi$ m

Therefore, Required number of revolution $=\frac{\text{Distance covered by the front wheel in 800 revolutions}}{\text{Circumference of the rear wheel}}=\frac{640\pi }{2\pi }=320$